two arithmetic progression are such that the common difference of both is 8.if the difference b/w their 50th terms is 50.what will be the difference b/w their 80th terms?

Answer 1

let the first term of the first progression be a
let the 2nd term of the other progression be b

a + 49(8) - (b + 49(8)) = 50
a - b = 50

a+79(8) - (b+79(8))
= a - b
= 50

The difference between like term numbers stays the same at 50

Answer 2

Hey u tell how it happened like that if u tell it directly how can we understand? U don't have that much common sense.
So tell how it happened and get lost u bloody hell ✌.

Answer 3

This isn't the correct solution.