The quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dissolved in hot, concentrated acid and passed over a reducing agent so that all the antimony is in the form Sb3 (aq). The Sb3 (aq) is completely oxidized by an aqueous solution of BrO3–(aq). Complete and balance the equation for this reaction in acidic solution.

asked by Katie

13 years ago

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1 answer

The two half equations you need are
Sb^+3 ==> Sb^5+ + 2e
6e + BrO3^- + 6H^+==> Br^- + 3H2O

answered by DrBob222

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Question

The quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dissolved in hot, concentrated acid and passed over a reducing agent so that all the antimony is in the form Sb3 (aq). The Sb3 (aq) is completely oxidized by an aqueous solution of BrO3–(aq). Complete and balance the equation for this reaction in acidic solution.

1 answer

The two half equations you need are
Sb^+3 ==> Sb^5+ + 2e
6e + BrO3^- + 6H^+==> Br^- + 3H2O

Ask a New Question or answer this question.

DrBob222 · Answer

The two half equations you need are Sb^+3 ==> Sb^5+ + 2e 6e + BrO3^- + 6H^+==> Br^- + 3H2O