The quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dissolved in hot, concentrated acid and passed over a reducing agent so that all the antimony is in the form Sb3 (aq). The Sb3 (aq) is completely oxidized by an aqueous solution of BrO3–(aq). Complete and balance the equation for this reaction in acidic solution.
BrO3^- + 3Sb^3-> Br^- + 3Sb^5+
I tried BrO3^- + 3Sb^3+ +6H -> Br^- + 3Sb^5+ +3H2O but it is wrong.
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