The perimeter of a rectangle is 66m. if the width were doubled and the length were increased by 24m, the perimeter would be 132m. What are the length and width of the rectangle

Answer 1

original:
length --- x
width ---- y
2x + 2y = 66
x+y = 33
y = 33-x

new rectangle:
length ---- x+24
width = 2y
perimeter= 2(x+24) + 2(2y) = 132
2x + 48 + 4y = 132
2x + 48 + 4(33-x) = 132
-2x + 180 = 132

take over

Answer 2

who dis