Asked by lucky
the perimeter of a rectangle is 70m. if the width were doubled and length were increased by 24m, the perimeter would be 142m. what are the length and width of the rectangle?
Answers
Answered by
TutorCat
W+W+L+L=70
(2W)+(2W)+(L+24)+(L+24)=142
Solve for W in terms of L.
W+W+L+L=70
W=(70-2L)/2
Use substitution to find L.
(2[(70-2L)/2])+(2[(70-2L)/2])+(L+24)+(L+24)=142
Then Plug the L value back into W=(70-2L)/2 to find W
(2W)+(2W)+(L+24)+(L+24)=142
Solve for W in terms of L.
W+W+L+L=70
W=(70-2L)/2
Use substitution to find L.
(2[(70-2L)/2])+(2[(70-2L)/2])+(L+24)+(L+24)=142
Then Plug the L value back into W=(70-2L)/2 to find W