Call the width W
Call the length L
Then you know tow things:
W * L = 1000
and
3 * W + 2 * L = 160
then L = W/1000
so
3*W + 2000/W = 160
or
3 * W^2 - 160 * W + 2000 = 0
Solve that quadratic with the quadratic equation. You get two results. One of them has a short side, W, longer than the long side, L. Throw that solution out because long is longer than short. The other solution, W = 20 and then L = 50 works.
The Parkhursts used 160 yd of fencing to enclose a rectangular corral and to divide it into two parts by a fence parrallel to one of the shorter sides. Find the dimensions of the corral if its area is 1000 yd^2
Thank you!
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