Do you mean two parts instead of two paths? Is the 160 yards supposed to include the outer perimeter?
If so,
3a + 2b = 160 (a is the short side)
ab = 1000
Solve the simulataneous equations.
I had 12 of these problems got through all but the last one.
I need to show the steps
The Parkhursts used 160 yd of fencing to enclose a rectangular corral to divide it into two paths by a fence parallel to one of the shorter sides. Find the dimensions of the corral if its area is 1000 yd ^2 ( yd has a small 2 above the d)
show each step
3 answers
I am having problems with the steps in this problem you are correct I made a typo it is parts - not path
thanks sam
thanks sam
The first equation I wrote says that the lotal length of fencing equals 160 yards. The second says the total area of the divided corral is 1000 yard^2. The rest of the problem becomes an exercise in solving simultaneous equations. Substitute 1000/a for b in the first equation and you will have an equation for a only.
3a + 2000/a = 160
Try to do the remaining steps yourself. Hint: convert to a quadratic equation). We will be glad to critique your work.
3a + 2000/a = 160
Try to do the remaining steps yourself. Hint: convert to a quadratic equation). We will be glad to critique your work.