width --- x
length = 4x + 9
2x + 2(4x+9) = 538
10x + 18 = 538
x = 52
The length of a new rectangular playing field is 9 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 538 yards, what are its dimensions?
The width is ? yards.
1 answer
1 answer