A new Outdoor Recreation Center is being built in Erie. The perimeter of the rectangular playing field is "342" yards. The length of the field is 6 yards less than double the width. What are the dimensions of the playing field?

Answer 1

Let's call the width of the playing field "x".

According to the problem, the length of the field is 6 yards less than double the width. So, the length is 2x - 6.

The perimeter of a rectangle is given by the formula: P = 2*(length + width)

Since the perimeter of the playing field is 342 yards, we can write the equation: 342 = 2*(2x - 6 + x)

Expanding the equation, we get: 342 = 2*(3x - 6)

Now, let's solve for x:

342 = 6x - 12

6x = 342 + 12

6x = 354

x = 354/6

x ≈ 59

So, the width of the playing field is approximately 59 yards.

Now, using this value, let's find the length of the field:

Length = 2x - 6
Length = 2*59 - 6
Length = 118 - 6
Length = 112

So, the dimensions of the playing field are approximately 112 yards by 59 yards.