The leader of a bicycle race is traveling with a constant velocity of +11.9 m/s and is 10.7 m ahead of the second-place cyclist. The second-place cyclist has a velocity of +9.10 m/s and an acceleration of +1.20 m/s2. How much time elapses before he catches the leader?

Answer 1

(v2•t+at²/2) - v1•t = 10.7
at²/2+ (v2-v1)t -10.7 = 0
0.6t² -2.8t- 10.7 =0
t= [2.8±√(2.8² +4•0.6•10.7)]/1.2.
The positive root is 7.16 s.

Answer 2

Wrong