The leader of a bicycle race is traveling with a constant velocity of +11.9 m/s and is 10.7 m ahead of the second-place cyclist. The second-place cyclist has a velocity of +9.30 m/s and an acceleration of +1.20 m/s2. How much time elapses before he catches the leader?

Answer 1

v₂t +at²/2 -v₁t =10.7
0.6t²-2.6t -10.7 =0
t=6.92 s