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The leader of a bicycle race is traveling with a constant velocity of +12.0 m/s and is 11.8 m ahead of the second-place cyclist. The second-place cyclist has a velocity of +9.90 m/s and an acceleration of +1.20 m/s2. How much time elapses before he catches the leader?

1 answer

D2 = D1 + 11.8.
Vo*t + 0.5a*t^2 = 12t + 11.8
9.9t + 0.6t^2 = 12t + 11.8
0.6t^2 + 9.9t -12t = 11.8
0.6t^2 - 2.1t - 11.8 = 0
Use Quadratic Formula and get:
t = 6.52 s.
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