The height, in meters, of a projectile can be modeled by h= -4.9t^2 + vt + s where t is the time (in seconds) the object has been in the air, v is the initial velocity (in meters per seconds) and s is the initial height (in meters). A soccer ball is kicked upward from the ground and flies through the air with an initial velocity of 4.9 meters per second. Approximately, after how many seconds does it land?

3 answers

so your height formula is
h = -4.9t^2 + 4.9t + 0 , assuming kicked from ground
when it lands, h = 0
-4.9t^2 + 4.9t = 0
-4.9t(t - 1) = 0
t = 0 ----> at the moment the ball is kicked
or
t = 1, it lands 1 second later
it lands when h=0. So, just solve the quadratic the way you do normally.
Thanks!