Asked by Nish
the height, h, in meters, of a gold ball t seconds after is is hit can be modelled by the function:
h (t) = 4.9t^2 + 32t + 0.2.
When is the height of the ball 15 m?
h (t) = 4.9t^2 + 32t + 0.2.
When is the height of the ball 15 m?
Answers
Answered by
Reiny
You have a typo, there should be a negative sign in front of 4.9t^2
so you want h(t) to be 5, ...
15 = -4.9t^2 + 32t + .2
4.9t^2 - 32t + 14.8 = 0
solve using the quadratic formula, you should get two positve answers, one will be the time on its upwards path, the other will be the time on its downwards path.
(should be appr. t=0.5 and t=6)
so you want h(t) to be 5, ...
15 = -4.9t^2 + 32t + .2
4.9t^2 - 32t + 14.8 = 0
solve using the quadratic formula, you should get two positve answers, one will be the time on its upwards path, the other will be the time on its downwards path.
(should be appr. t=0.5 and t=6)
Answered by
Nish
thanks so much Reiny! :D for correcting my mistake and for the answer!
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