Question

The height (in meters) of a projectile shot vertically upward from a point 3 m above ground level with an initial velocity of 21.5 m/s is
h = 3 + 21.5t − 4.9t2
after t seconds. (Round your answers to two decimal places.)
(a) Find the velocity after 2 s and after 4 s.
v(2) = m/s
v(4) = m/s


(b) When does the projectile reach its maximum height?
s

(c) What is the maximum height?
m

(d) When does it hit the ground?
s

(e) With what velocity does it hit the ground?
m/s

Answer 1

The height (in meters) of a projectile shot vertically upward from a point 4 m above ground level with an initial velocity of 21.5 m/s is
h = 4 + 21.5t − 4.9t2
after t seconds. (Round your answers to two decimal places.)
(a) Find the velocity after 2 s and after 4 s.
v(2) =
1.9
m/s
v(4) =
-17.7
m/s


(b) When does the projectile reach its maximum height?

2.19
s

(c) What is the maximum height?

27.58
m

(d) When does it hit the ground?

109.64
s

(e) With what velocity does it hit the ground?

m/s