Asked by Please help mee
the height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with initial velocity of 24.5 m/s is
h=2+24.5t-4.9t^2 after t seconds. Find the velocity after 2s and 4 s?
h=2+24.5t-4.9t^2 after t seconds. Find the velocity after 2s and 4 s?
Answers
Answered by
Steve
gotta remember that
v(t) = h'(t) = 24.5 - 9.8t
now just plug in t=2 or 4
v(t) = h'(t) = 24.5 - 9.8t
now just plug in t=2 or 4
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