Question

the height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with initial velocity of 24.5 m/s is
h=2+24.5t-4.9t^2 after t seconds. Find the velocity after 2s and 4 s?

Answer 1

gotta remember that

v(t) = h'(t) = 24.5 - 9.8t

now just plug in t=2 or 4