The height in feet of a projectile with an initial velocity of 32 feet per second and an initial height of 240 feet is a function of time in seconds given by

Question

h(t) = −16t2 + 32t + 240.

(a) Find the maximum height of the projectile. ______ ft

(b) Find the time t when the projectile achieves its maximum height.
t = ______ sec

(c) Find the time t when the projectile has a height of 0 feet.
t = ______ sec

Answer 1

the max height is achieved at the vertex of the parabola, when t = 1

for (c), just solve

16t^2 - 32t - 240 = 0
16(t+3)(t-5) = 0
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