the max height is where t = -b/2a = 3
h(3) = 256 ft
h=0 when t=7
The height in feet of a projectile with an initial velocity of 96 feet per second and an initial height of 112 feet is a function of time in seconds given by
h(t) = −16t2 + 96t + 112.
(a) Find the maximum height of the projectile.
144
Incorrect: Your answer is incorrect.
ft
(b) Find the time t when the projectile achieves its maximum height.
t =
sec
(c) Find the time t when the projectile has a height of 0 feet.
t =
sec
1 answer