The half-life of a certain radioactive isotope is 32 hours.What fraction of the sample would remain after 16 hours?(a)0.50(b)0.25(c)0.62(d)0.71

Answer 1

N=N(initial)(.5)^(t/half-life)
(N/N(initial))= (.5)^(16/32)
= .707
= 70.7% of original

Answer 2

not understood

Answer 3

0.71

Answer 4

I can easily understood ,thank you