F = k * w * v^2 /R
182 = k (1800) (900)/600
k = .0674
F = .0674 (1800) (2025)/650
= 378 pounds
The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of its speed and inversely as the radius of the curve. If 182lb of force keep a 1800lb car from skidding on a curve of radius 600ft at 30 mph, what force would keep the same car from skidding on a curve of radius 650ft at 45 mph?
2 answers
The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of its speed and inversely as the radius of the curve. Given that it takes 2800 pounds of force to keep an 1800-pound car from skidding on a curve with a radius of 425 feet at 45 mph. We have to determine the force, rounded to the nearest 10 pounds that is needed to keep the same car from skidding when it takes a similar curve with a radius of 450 feet at 55 mph.
1 answer