F = k m g v^2/R
(actually k g = 1 because v^2/R is centripetal acceleration)
anyway
400 = k (1600) 50^2/800
so k(1600) = 800 * 400 /2500
F = k (1600) 60^2 /600
F = 800*400 *3600 /{2500*600)
= (8/6)(36/25)*400
= (4/3)(36)(16) = 768 pounds
The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the car's speed.Suppose that 400 pounds of force keeps a 1600-pound car from skidding on a curve of radius 800ft
at 50mph. What force would keep the same car from skidding on a curve of radius 600ft at 60mph?
1 answer
6 answers