The total resistance for the circuit can be calculated as:
Total resistance = (resistance of one resistor) + (resistance of two parallel resistors)
Total resistance = 10Ω + (10Ω || 10Ω)
Total resistance = 10Ω + (5Ω)
Total resistance = 15Ω
Using Ohm's Law (V = IR), we can calculate the current going through the circuit:
I = V / R
I = 12V / 15Ω
I = 0.8 Amps
Therefore, the current going through the resistor in region A is 0.8 Amps.
The following circuit contains a battery and six identical resistors. If the battery provides a 12 V electromotive force and the resistors are each 10Ω, what is the current going through the resistor in region A in Amps?
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