To assist you effectively, I would need to make some assumptions about the values of the resistors and the voltage of the battery, as no specific values were provided in your question. However, I will provide general information and approaches to answer your questions.
Question 4.1: Define the term OHM’s LAW in words. [2 marks]
Ohm's Law states that the current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor. This relationship can be mathematically expressed as:
\[ V = I \times R \]
where \( V \) is the voltage across the conductor, \( I \) is the current flowing through it, and \( R \) is its resistance.
Question 4.2: Calculate the effective resistance of the circuit. [4 marks]
To calculate the effective resistance of the circuit, we need to know how the resistors are arranged (series or parallel) and their individual resistance values. Here's how to calculate for each case:
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For Resistors in Series: The total (or effective) resistance \( R_{total} \) is the sum of the individual resistances: \[ R_{total} = R_1 + R_2 + R_3 \]
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For Resistors in Parallel: The total resistance can be calculated using the formula: \[ \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \] or \[ R_{total} = \frac{1}{\left( \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \right)} \]
Question 4.3: Calculate the current reading on the ammeter. [2 marks]
To find the current reading on the ammeter, you will also need to know the effective resistance calculated from question 4.2 and the voltage of the battery. Using Ohm's law:
\[ I = \frac{V}{R_{total}} \]
- \( I \) is the current in amperes (A),
- \( V \) is the voltage of the battery in volts (V),
- \( R_{total} \) is the effective resistance in ohms (Ω).
If you provide specific values for the resistances and the battery voltage, I can give you numerical answers for the calculations!
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