To find the equation of the line containing the segment AB, we need to determine the slope of the line that passes through points A(3, 7) and B(6, 1).
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Calculate the slope (m) of line AB:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 7}{6 - 3} = \frac{-6}{3} = -2 \]
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Use the point-slope form of the equation of a line:
The point-slope form is given by: \[ y - y_1 = m(x - x_1) \]
We can choose point A(3, 7) for this process:
\[ y - 7 = -2(x - 3) \]
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Simplify the equation:
\[ y - 7 = -2x + 6 \] \[ y = -2x + 6 + 7 \] \[ y = -2x + 13 \]
The equation of the line that contains segment AB (and consequently line CD as per the information given, assuming they are parallel) is:
\[ \boxed{y = -2x + 13} \]