The curve f(x)=-x^4+2x^2+x has a tangent at the point (1,2). Is this line tangent to the curve at another point and, if so where?

2 answers

dy/dx = 4x^3 + 4x + 1
so at (1,2) dy/dx = 4+4+1 = 9

so is 4x^3 + 4x + 1 = 9 ?
x^3 + x - 2 = 0
we already know that (x-1) is a factor, so by synthetic division I found
x^3 + x - 2 = 0
(x-1)(x^2 + x + 2) = 0
x = 1, we knew that or
x = (-1±√-7)/2 which is not real

so there are no other points where the tangent has a slope of 9
find the tangent line, graph both of them
Similar Questions
  1. original curve: 2y^3+6(x^2)y-12x^2+6y=1dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
    1. answers icon 1 answer
  2. Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 .a. Show that dy/dx= (4x-2xy)/(x^2+y^2+1) b. Write an equation of each
    1. answers icon 3 answers
  3. original curve: 2y^3+6(x^2)y-12x^2+6y=1dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
    1. answers icon 0 answers
  4. original curve: 2y^3+6(x^2)y-12x^2+6y=1dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
    1. answers icon 3 answers
more similar questions