original curve: 2y^3+6(x^2)y-12x^2+6y=1
dy/dx=(4x-2xy)/(x^2+y^2+1)
a) write an equation of each horizontal tangent line to the curve
b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.
-when plugging y as 2 in original, it doesn't work. what did i do wrong?
1 answer
I do not agree with your equation for dy/dx. You appear to have done the implicit differdntiation incorrectly
0 answers