27/sqrt2 = 19.1 from home to mound
tan a = 15/19.1
The bases on a baseball diamond are 27.4m apart. The pitcher pitches,and the batter hits a fly ball straight up 15m. What is the maximum angle of elevation of the ball to the nearest degree, as seen by the pitcher if he is standing at the center of the diamond?
HELP
2 answers
distance to the plate: 27sqrt2 /2
= 27.4/2 sqrt2== 19.3718
theta=arc tan 15/19.37=37.75 degrees
= 27.4/2 sqrt2== 19.3718
theta=arc tan 15/19.37=37.75 degrees