The bases on a baseball diamond are 27.4m apart. The pitcher pitches,and the batter hits a fly ball straight up 15m. What is the maximum angle of elevation of the ball to the nearest degree, as seen by the pitcher if he is standing at the center of the diamond?

Question

HELP

Answer 1

27/sqrt2 = 19.1 from home to mound

tan a = 15/19.1

Answer 2

distance to the plate: 27sqrt2 /2
= 27.4/2 sqrt2== 19.3718

theta=arc tan 15/19.37=37.75 degrees