For a question this long, you really need to show some work of your own. You certainly can compute the time it takes the ball to reach the batter. (Part a)
i don't see why a home run should have to clear the fence by one foot (unless an outfielder can reach a foot higher than the fence)
Your first job in (b) is to calculate the velocity of the batted ball that is required to clear the fence by one foot. Use 32.2 ft/s^2 for g.
A pitcher throws a baseball to a batter at 95 mph from a distance, d, away. The batter swings and hits the ball. (5280 ft = 1 mi, g = 32.174 ft/s/s).
a) Assuming the pitch travels the full distance, d, how much reaction time does the batter have to hit the ball?
b) What minimum percentage of pitch velocity much be transferred to the ball for the batter to hit a homerun? Assume the point where it clears the fence is 395 ft away and the fence at this point is 12 ft high. For the ball to clear the fence, assume it has to be at least 1 ft higher than the fence at the time it passes over the fence. Also assume the pitch was waist high, 3 ft from the ground, when it was hit and made an initial angle of 35° with the ground.
c)what is the maximum height that the homerun ball attained?
d) How long did it take for the homerun to clear the wall?
e) How far did the homerun travel in total? Assume that there is no fan interference. Assume the height of the ball at this point is the same as the height of the ground.
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I have noooooo idea where to start.. this isn't even for a grade.. it was a free response on a test i got back.
Looks more like a long question than a response to one.
whatever you want to call it; it was 1/3 of the test.
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