The balanced net ionic equation resulting from addition of aqueous hydrochloric acid to solid chromium(III) hydroxide is:

Question

A. Cr(OH)3 (s) + 3 HCl (aq) 3 H2O (l) + CrCl3 (aq)
B. Cr(OH)3 (s) + 3 Cl- (aq) 3 OH- (l) + CrCl3 (aq)
C. Cr(OH)3 (s) + 3 H+ (aq) + 3 Cl- (aq) 3 H2O (l) + Cr3+(aq) + 3 Cl- (aq)
D. Cr(OH)3 (s) + 3 H+(aq) 3 H2O(l) + Cr3+(aq)
E. Cr(OH)3 (s) + 3 H+(aq) + 3 Cl- (aq) 3 H2O (l) + CrCl3 (s)

Answer 1

It would help if I knew what you don't understand about this. Also it would help if you found and used the arrow key(s) To write the net ionic equation you balance the molecular equation (which happens to be A) as step 1, for step 2 convert the molecular equation into a full ionic equation, and for step 3 cancel any materials common to both sides to leave the net ionic equation.

Answer 2

this mofo forgot the damn arrows lmfaoooo
The answer is D tho. I'm mad smart, so you can trust.

Also why Dr. Bob be getting downvoted to sht?