Nitric acid appears to “dissolve” solid lead(II) hydroxide.

Question

Products, Balanced equation, Total ionic equation and
Net ionic equation

Answer 1

The reaction between nitric acid and solid lead(II) hydroxide can be represented by the following balanced equation:

2 HNO3 + Pb(OH)2 -> Pb(NO3)2 + 2 H2O

In this reaction, nitric acid (HNO3) reacts with solid lead(II) hydroxide (Pb(OH)2) to form lead(II) nitrate (Pb(NO3)2) and water (H2O).

The total ionic equation for this reaction can be written as:

2 H+ + 2 NO3- + Pb2+ + 2 OH- -> Pb2+ + 2 NO3- + 2 H2O

In the total ionic equation, all soluble ionic compounds are written as separate ions.

The net ionic equation is obtained by removing the spectator ions (ions that are present on both sides of the equation) from the total ionic equation. In this case, the net ionic equation is:

2 H+ + 2 OH- -> 2 H2O

The lead(II) nitrate (Pb(NO3)2) does not participate in the net ionic equation as it remains in solution.