The reaction between nitric acid (HNO3) and lead(II) hydroxide (Pb(OH)2) can be represented by the following equation:
2 HNO3 + Pb(OH)2 → Pb(NO3)2 + 2 H2O
The products of this reaction are lead(II) nitrate (Pb(NO3)2) and water (H2O).
Nitric acid appears to “dissolve” solid lead(II) hydroxide.
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