3Cu + 8HNO3 ==> 3Cu(NO3)2 + 2NO + 4H2O
mols Cu = grams/molar mass
Using the coefficients in the balanced equation, convert mols Cu to mols NO.
Now convert mols NO to L at STP. 1 mol NO gas at STP occupies 22.4 L.
1. When solid copper metal reacts with nitric acid, the products include copper (II) ion and nitrogen monoxide gas. If 11.99 g of solid copper are reacted with 153 mL of 0.322 M HNO3, how many liters of nitrogen monoxide will be produced?
2. When solid copper metal reacts with nitric acid, the products include copper (II) ion and nitrogen monoxide gas. If 11.99 g of solid copper are reacted with 153 mL of 0.322 M HNO3, how many liters of nitrogen monoxide will be produced? (Assume the released gas is at standard temperature and pressure.)
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