To find the distance the tectonic plate moves in 2 * 10^6 years, we can multiply the rate of movement per year (0.006 m) by the number of years (2 * 10^6).
0.006 m/year * 2 * 10^6 years = 0.012 * 10^6 m
We can simplify this expression to scientific notation by moving the decimal point to the left one place and adjusting the exponent accordingly:
0.012 * 10^6 m = 1.2 * 10^5 m
Therefore, the tectonic plate would move 1.2 * 10^5 meters in 2 * 10^6 years.
The average tectonic plate moves at the rate of 0.006 m per year. How many meters would it move in 2 * 10 ^ 6 years? Write the answer in scientific notation, expressed to the exact decimal place. (1 point)
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