To find the total distance that the tectonic plate would move in 2×10^6 years, we can multiply the average rate of movement (0.006 m/year) by the number of years (2×10^6 years).
(0.006 m/year) * (2×10^6 years) = 0.006 * 2 * 10^6 m
Simplifying the equation, we get:
= 0.012 * 10^6 m
To express this number in scientific notation, we can convert 0.012 to 1.2 and adjust the exponent as necessary. In this case, we move the decimal place 3 places to the right and increase the exponent by 3.
= 1.2 * 10^3 m
Therefore, the tectonic plate would move 1.2 * 10^3 meters in 2×10^6 years.
The average tectonic plate moves at the rate of 0.006 m per year. How many meters would it move in 2×10^6 years? Write the answer in scientific notation, expressed to the exact decimal place.
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