The average tectonic plate moves at the rate of 0.006 m per year how many meters would it move in 2 times 10^6 years

Answer 1

To find the total distance the tectonic plate moves in 2 times 10^6 years, we can multiply the average rate of movement by the number of years.

Distance = Rate * Time

Distance = 0.006 m/year * 2 * 10^6 years

Distance = 0.006 * 2 * 10^6 m

Distance = 12 * 10^4 m

Distance = 1.2 * 10^5 m

So, the tectonic plate would move 1.2 * 10^5 meters in 2 times 10^6 years.