w (w+6) = 216
w^2 + 6 w - 216 = 0
(w-12)(w+18) = 0
w = 12, L = 18
The area of a playground is 216 yd2. The width of the playground is 6 yd longer than its length. Find the length and width of the playground, including appropriate units. Then, enter the sum of the length and width in the provided grid. Show your work
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