The surface area covered by rectangular playground is 200 yards. The weight of the playground is twice as long as it’s only using factors determine the length and the width of the playground.

Answer 1

To determine the length and width of the playground, we need to find two factors whose product equals half of the weight of the playground.

Let x be the length and y be the width of the playground.
We know that x*y = 200. This is our first equation.

We are also told that the weight of the playground is twice as long as it is wide, so the weight equals 2y.
Half of the weight is y, so our second equation is y = y.

Now, we can substitute y = 200/x into the second equation:
y = 200/x

Substituting this expression for y into the first equation, we have:
x * (200/x) = 200
200 = 200

Simplifying, we find:
x^2 = 200

Taking the square root of both sides, we get:
x = ±√200

Since we are dealing with measurements, we cannot have negative values, so we discard x = -√200 and only consider the positive value:
x = √200

To find the other factor, we substitute this value of x into the first equation:
√200 * y = 200
y = 200 / √200

Simplifying, we have:
y = √200

Therefore, the length of the playground is approximately √200 yards and the width is approximately 200 / √200 yards.