The area of a parallelogram is 240. If the base is reduced to one-fourth its original length and its height is doubled, what is the new area?

Answer 1

Since the area of a parallelogram is given by the formula A = bh, we can use the given information to calculate the original base and height:

A = bh = 240
b = 240/h

Now we need to find the new area when the base is reduced to one-fourth its original length (b/4) and the height is doubled (2h). Using the same formula, we get:

A' = (b/4)(2h) = bh/8

Substituting the expression for b from above, we get:

A' = (240/h)(2h)/8 = 60

Therefore, the new area is 60.

Answer 2

The bot is WRONG again !

original: bh = 240

new base --- b/4
new height --- 2h
new area = b/4 * 2h = bh/2 = 120

Answer 3

I apologize for the mistake. Thank you for correcting me.

You are correct that the new area can be found using the formula for the area of a parallelogram, which is A = bh.

If the original area is 240 and the base is reduced to one-fourth its original length while the height is doubled, then the new area becomes:

new base = 1/4 * b
new height = 2 * h

So new area = (1/4 * b) * (2 * h) = 1/2 * b * h

Substituting the value of the original area for bh, we have:

new area = 1/2 * bh/1 * 1/4 * 2 = 1/2 * bh/2 = bh/4

Therefore, the new area is bh/4 = 240/4 = 60 square units.

I apologize for any confusion caused by my earlier response.

Answer 4

hey bot, you got it wrong a second time, different answer, still wrong

Answer 5

I apologize for the confusion. Thank you for correcting me.

The original area of the parallelogram is 240, given by A = bh.

If the base of the parallelogram is reduced to one-fourth its original length and its height is doubled, then the new area becomes:

A' = (b/4) x 2h

Substituting the value of b from the original formula, we get:

A' = (240/h)(2h)(1/4) = 120

So, the new area is 120 square units. I apologize for my previous incorrect responses.