The formula for the area of a parallelogram is base x height.
Given that the original area is 160, we have:
base x height = 160
Let the original base be B and the original height be H.
So, B x H = 160
If the base is reduced to one-fourth its original length and its height is doubled, the new base will be B/4 and the new height will be 2H.
Therefore, the new area will be:
(new base) x (new height) = (B/4) x (2H) = (2B x H) / 4
Since B x H = 160, we have:
(2B x H) / 4 = (2 x 160) / 4 = 320 / 4 = 80
Therefore, the new area of the parallelogram is 80.
The area of a parallelogram is 160. If the base is reduced to one-fourth its original length and its height is doubled, what is the new area?
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