The formula for the area of a parallelogram is given by:
Area = base x height
Let the original base of the parallelogram be b and the original height be h. Given that the area is 160, we have:
160 = b*h
Now if the base is reduced to one-fourth its original length and the height is doubled, the new base becomes b/4 and the new height becomes 2h. Therefore, the new area is:
New Area = (b/4)*(2h) = (b*h)/2
Substitute the original area value into the equation:
New Area = 160/2 = 80
Therefore, the new area of the parallelogram is 80.
The area of a parallelogram is 160. If the base is reduced to one-fourth its original length and its height is doubled, what is the new area?(1 point)
1 answer