Assuming you meant
sinθ=3/4
The hypotenuse is 4, so the other leg is √(16-9) = √7
In QII, x<0. Since cosθ = x/r
cosθ = -√7/4
You should immediately have known your answer was wrong, because
sin^2θ + cos^2θ = 1
The angle θ lies in Quadrant II .
sinθ=34
What is cosθ ?
−7√/4
7√/4
3/4
−3/4 <my answer
1 answer
1 answer