The angle θ lies in Quadrant II .

sinθ=34

What is cosθ ?



−7√/4

7√/4

3/4

−3/4 <my answer

1 answer

Assuming you meant

sinθ=3/4
The hypotenuse is 4, so the other leg is √(16-9) = √7

In QII, x<0. Since cosθ = x/r
cosθ = -√7/4

You should immediately have known your answer was wrong, because

sin^2θ + cos^2θ = 1
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