in QII, x is negative, so cosθ = -3/5
The rest is easy, right?
find the values of the requested trig functions using the given value and quadrant in which the point corresponding to the angle lies.
quadrant II; sinθ=4/5
find cosθ and tan θ
3 answers
i don't understand where you got the -3/5 from
better review your trig functions
sinθ = x/r
cosθ = y/r
r^2 = x^2+y^2
You have a 3-4-5 triangle.
Draw the dang thing!
x = -3, so cosθ = -3/5
sinθ = x/r
cosθ = y/r
r^2 = x^2+y^2
You have a 3-4-5 triangle.
Draw the dang thing!
x = -3, so cosθ = -3/5