To find the number of moles of chlorine used in the reaction, we first need to calculate the molar mass of chlorine:
Cl2: 35.45 g/mol (molar mass of Cl) * 2 = 70.90 g/mol
Next, we convert the given mass of chlorine to moles:
20.50 g Cl2 * (1 mol Cl2 / 70.90 g Cl2) = 0.289 moles Cl2
Therefore, the moles of chlorine used in the reaction is 0.289 (to three significant figures).
The anesthetic chloroform (CHCI3, molar mass=119.36 g/mol) can be prepared by the reaction of methane CH4 molar mass= 16.04 g/mol with chlorine according to the following balanced equation: CH4+3CI2 CHCI3+3HCI
Assuming 10.50g of methane and 20.50g of chlorine are used, answer the following questions:
How many moles of chlorine are used? Be sure your answer has the correct number of significant figures.
moles of chlorine 0.289 is not the correct significant figure
1 answer
1 answer