The anesthetic chloroform (CHCI3, molar mass=119.36 g/mol) can be prepared by the reaction of methane CH4 molar mass= 16.04 g/mol with chlorine according to the following balanced equation: CH4+3CI2 CHCI3+3HCI

Assuming 10.50g of methane and 20.50g of chlorine are used, answer the following questions:

How many moles of chlorine are used? Be sure your answer has the correct number of significant figures.

moles of chlorine

1 answer

To find the number of moles of chlorine used, we can first calculate the molar mass of chlorine (Cl2):

Molar mass of Cl2 = 35.45 g/mol (molar mass of Cl) * 2 = 70.90 g/mol

Next, we can convert the given mass of chlorine (20.50g) to moles:

moles of Cl2 = 20.50g / 70.90 g/mol = 0.289 mol

Therefore, 0.289 moles of chlorine are used in the reaction.