First, we need to determine the limiting reactant by calculating the moles of methane and chlorine used in the reaction:
Moles of methane = 10.50g / 16.04 g/mol = 0.654 moles
Moles of chlorine = 20.50g / 70.90 g/mol = 0.289 moles
Since there are 3 moles of chlorine required for every mole of methane in the reaction, we can see that chlorine is the limiting reactant as it is present in a smaller amount.
Now, we can calculate the moles of chloroform formed using the mole ratio from the balanced equation:
1 mole of methane produces 1 mole of chloroform
0.289 moles of chlorine * (1 mole of chloroform / 3 moles of chlorine) = 0.0963 moles of chloroform
Therefore, 0.0963 moles of chloroform are formed.
The anesthetic chloroform (CHCI3, molar mass=119.36 g/mol) can be prepared by the reaction of methane CH4 molar mass= 16.04 g/mol with chlorine according to the following balanced equation: CH4+3CI2 CHCI3+3HCI
Assuming 10.50g of methane and 20.50g of chlorine are used, answer the following questions:
How many moles of chloroform are formed? Be sure your answer has the correct number of significant figures.
moles of chloroform
1 answer