•(0.03644L)(0.013 mol/L) = 4.7372x10^-4 mol Fe+3
•(4.7372x10^-4 mol Fe+3)(1 mol H2C2O4 / 2 mol Fe+3) = 2.37x10^-4 mol H2C2O4
•Find the molar mass of H2C2O4 and multiply by the moles of H2C2O4 to get the mass in grams. The mass of H2C2O4 over the mass of the sample, times 100 is the % of H2C2O4.
The amount of oxalic acid in a sample was determined by the reaction:
2Fe3+ + H2C2O4 + 2H2O----> 2Fe2+ + 2CO2 + 2H3O+.
In an analysis, 10.62g of sample required 36.44 ml of 0.013 M Fe3+. Calculate the %w of oxalic acid in the sample.
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