a 69.3g sample of oxalic ac acid, H2C2O4, was dissolved in 1.000L of solution. How would yo prepare 1.00L of 0.150M H2C2O4 from this solution?

Answer 1

figure moles in 69.3g.
moles: 69.3/90=you do it.

Molarity of original solution: 69.3/90=.77M

So you want to decrease molarity to .150, you do that by diluting with water.

You want to dilute it .77/.150 times, or 5.13 times, which means 4.13 parts water, and 1 part original solution.

making one liter, you need each part to be 1000ml/5.13=195ml

Take 195 ml of the original solution, and add water to the 1 liter mark, stir, label, and properly store.

check my figuring.