The altitude of an airplane is decreasing at a rate of 42 feet per second. What is the change in altitude of the airplane over a period of 28 seconds?

Question

A.
-70 feet
B.
-1,176 feet
C.
1,176 feet
D.
70 feet

Answer 1

To find the change in altitude of the airplane over a period of 28 seconds, we can use the formula:

\[ \text{Change in altitude} = \text{Rate of change} \times \text{Time} \]

Given that the altitude is decreasing at a rate of 42 feet per second and the time period is 28 seconds, we can plug in the values:

\[ \text{Change in altitude} = -42 , \text{feet/second} \times 28 , \text{seconds} \]

Calculating this gives:

\[ \text{Change in altitude} = -42 \times 28 = -1,176 , \text{feet} \]

Thus, the change in altitude of the airplane over the period of 28 seconds is \(-1,176\) feet.

The correct answer is:

B. -1,176 feet