Question

The altitude of an airplane is decreasing at a rate of 42 feet per second. What is the change in altitude of the airplane over a period of 15 seconds?
A.
-630 feet
B.
-57 feet
C.
630 feet
D.
57 feet

Answer 1

To find the change in altitude of the airplane over a period of 15 seconds, we can use the following formula:

\[
\text{Change in altitude} = \text{rate of change} \times \text{time}
\]

Given that the altitude is decreasing at a rate of 42 feet per second, and the time period is 15 seconds, we can calculate:

\[
\text{Change in altitude} = -42 \, \text{feet/second} \times 15 \, \text{seconds} = -630 \, \text{feet}
\]

Thus, the change in altitude over 15 seconds is \(-630 \, \text{feet}\).

The answer is: **A. -630 feet**.