Question

The altitude of an airplane is decreasing at a rate of 43 feet per second. What is the change in altitude of the airplane over a period of 33 seconds?
O A.
-76 feet
• B.
-1,419 feet
O c.
76 feet
O D.
1.419 feet

Answer 1

To find the change in altitude of the airplane over a period of 33 seconds, you can use the formula:

\[
\text{Change in altitude} = \text{rate of change} \times \text{time}
\]

In this case, the rate of change is \(-43\) feet per second (because the altitude is decreasing), and the time is \(33\) seconds.

Calculating the change in altitude:

\[
\text{Change in altitude} = -43 \, \text{feet/second} \times 33 \, \text{seconds} = -1,419 \, \text{feet}
\]

Thus, the change in altitude of the airplane over the 33 seconds is \(-1,419\) feet.

The correct answer is:

**B. -1,419 feet**